bantu jawab pake cara ya

(x - 3)^2 + (y - 3)^2 = 9
x^2 + y^2 = 9 => y^2 = 9-x^2
y = V(9-x^2)
(x -3)^2 + { V(9-x^2)- 3 }^2 = 9
x^2-6x+9 + (9-x^2) -6V(9-x^2) + 9 = 9
x^2-6x+9+9-x^2-6V(9-x^2) = 0
-6x +18 -6V(9-x^2) = 0
6x + 6V(9-x^2) = 18
x + V(9-x^2) = 3
(x + V(9-x^2) = 3
(x + V(9-x^2)^2 = 3^2
x^2 +2xV(9-x^2) + 9 - x^2 = 9
2xV(9-x^2) = 0
V(9-x^2) = 0
9-x^2 = 0
(3-x)(3+x) = 0
x1 = 3 atau x2 = - 3
y1 = V(9 -3^2) = 0
y2 = V(9 - (-3)^2) = 0
Jadi A = (-3, 0) dan B (3,0)
Jarak AB = 3 - -3 = 6