Matematika

Pertanyaan

Plis mohon di jawab.......
Plis mohon di jawab.......

1 Jawaban

  • 6.
    a. luas juring AOB
    = 80/360 × luas lingkaran
    = 2/9 × (3,14) (10)^2
    = 2/9 × (3,14) (100)
    = 2/9 × 314
    = 69,78 cm^2

    b. Pj apotema OC
    = akar 10^2 - 5^2
    = akar 100 - 25
    = akar 75
    = 8,66 cm

    c. luas segitiga OAB
    = 1/2 × a × t
    = 1/2 × 10 × 8,66
    = 43,30 cm^2

    d. luas tembereng AB
    = luas juring AOB - luas segitiga OAB
    = 69,78 - 43,30
    = 26,57 cm

    7.
    a. Pj busur BC
    = 30/60 × 8,7
    = 1/2 × 8,7
    = 4,35 cm

    b. Pj busur AB
    = 90/60 × 8,7
    = 3/2 × 8,7
    = 13,05 cm

    c. K-lingkaran
    = 360/60 × 8,7
    = 6 × 8,7
    = 52,2 cm

    d. luas juring AOC
    = 120/60 × 36
    = 2 × 36
    = 72 cm^2

    e. luas lingkaran
    = 360/60 × 36
    = 6 × 36
    = 216 cm^2


    mohon dicek lagi jawaban saya, maaf kl salah...
    silahkan tanya jk tdk mengerti
    TY