tolong y pakek caranya pliss bantuin donk

r = 9
t = 21 cm

V = π.r².t
V = 22/7 ×9×9×21
V = 5.346 cm³

Lp = 2 π r ( r + t )
Lp = 2×22/7×9 (9+21)
Lp = 56,57 × 30
Lp = 1697,1 cm²

Lp tanpa tutup
= π .r ( r+2t)
= 22/7×9 × (9+2×21)
= 28,29 × (9 + 42)
= 28.29 × 51
= 1.442,79 cm²

a.
[tex]v = \pi \times {r}^{2} \times t \\ v = \frac{22}{7} \times {9}^{2} \times 21 \\ v = 5346 \: {cm}^{3} [/tex]
b.
[tex]lp = 2 \times \pi \times r(t + r) \\ lp = 2 \times 3.14 \times 9 (21 + 9) \\ lp = 56.52 \times 30 \\ lp = 1695.6 \: {cm}^{2} [/tex]
c.
[tex]tanpa \: tutup = \pi \times r(2t + r) \\3.14 \times 9(2 \times 21 + 9) \\ 28.26 \times 51 \\ 1441.26 \: {cm}^{2} [/tex]
Thanks..jadikan yg trbaik❤