Mohon dijawab ya semua

x²-2x+3=0
x1 dan x2 akar2nya.
x1+x2=-b/a=-(-2)/1=2
x1.x2=c/a=3/1=3
2/(x1)²+2/(x2)²=
Samakan penyebut
[2(x2)²+2(x1)²]/[(x1)²(x2)²]
=[2(x1)²+2(x2)²]/[(x1)²(x2)²]
=2 (x1²+x2²)/x1.x1.x2.x2
=2 [(x1+x2)²-2x1.x2] / x1.x2.x1.x2
=2 [(2)²-2.3]/ 3.3
=2 (4-6)/9
=2.-2/9
=-4/9
C