Tolong bantuannya ya mk
Matematika
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Pertanyaan
Tolong bantuannya ya mk
1 Jawaban
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1. Jawaban AlfandyGulo
⏩Akar dan Pangkat
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[tex] = \frac{2 \sqrt{2} }{6 - 3 \sqrt{3} } \times \frac{6 + 3 \sqrt{3} }{6 + 3 \sqrt{3} } \\ \\ = \frac{12 \sqrt{2} + 6 \sqrt{6} }{36 - 27} \\ \\ = \frac{12\sqrt{2} + 6 \sqrt{6} }{9} \\ \\ = \frac{12}{9} \sqrt{2} + \frac{6}{9} \sqrt{6} \\ \\ = \frac{4}{3} \sqrt{2} + \frac{2}{3} \sqrt{6} \\ \\ = \frac{2}{3} \sqrt{2} (2 + \sqrt{3} )[/tex]