Matematika

Pertanyaan

fungsi g(x) = x2 - 2x dan fungsi (gof)(x) = x2 - 4x +3 tentukan f(x)

1 Jawaban

  • g (f(x)) = x^2 - 4x + 3
    g (x) = x^2 - 2x
    (f(x))^2 - 2(f(x)) = x^2 - 4x + 3

    misal f(x) itu A

    A^2 - 2A = x^2 - 4x + 3
    A^2 - 2A + 1 = x^2 - 4x + 3 +1
    ( A -1 )^2 = x^2 - 4x + 4
    ( A -1 )^2 = ( x - 2 )^2
    A - 1 = x - 2
    A = x -1

    jadi f (x) = x - 1 ( JAWABAN )

    buktikan, g (x) = x^2 - 2x
    g (f(x)) = (x -1)^2 - 2(x -1)
    gof (x) = x^2 - 2x + 1 - 2x + 2
    gof (x) = x^2 - 4x + 3 ( BENAR )

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