fungsi g(x) = x2 - 2x dan fungsi (gof)(x) = x2 - 4x +3 tentukan f(x)
Matematika
Himmatululya3552
Pertanyaan
fungsi g(x) = x2 - 2x dan fungsi (gof)(x) = x2 - 4x +3 tentukan f(x)
1 Jawaban
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1. Jawaban biqiks
g (f(x)) = x^2 - 4x + 3
g (x) = x^2 - 2x
(f(x))^2 - 2(f(x)) = x^2 - 4x + 3
misal f(x) itu A
A^2 - 2A = x^2 - 4x + 3
A^2 - 2A + 1 = x^2 - 4x + 3 +1
( A -1 )^2 = x^2 - 4x + 4
( A -1 )^2 = ( x - 2 )^2
A - 1 = x - 2
A = x -1
jadi f (x) = x - 1 ( JAWABAN )
buktikan, g (x) = x^2 - 2x
g (f(x)) = (x -1)^2 - 2(x -1)
gof (x) = x^2 - 2x + 1 - 2x + 2
gof (x) = x^2 - 4x + 3 ( BENAR )