pake cara ya jwabannya

[tex] A^{-1} = \frac{1}{ad-bc} \left[\begin{array}{ccc}d&-b\\-c&a\end{array}\right] \\ A^{-1} = \frac{1}{(-8)-(-6)} \left[\begin{array}{ccc}4&-3\\2&-2\end{array}\right] \\ A^{-1} = \frac{1}{-2} \left[\begin{array}{ccc}4&-3\\2&-2\end{array}\right] \\ A^{-1} = \left[\begin{array}{ccc}-2& \frac{3}{2} \\-1&1\end{array}\right] [/tex]

[tex]A^{-1}= \frac{1}{-2.4-(3.-2)} \left[\begin{array}{ccc}4&-3\\2&-2\end{array}\right] \\ A^{-1}=-\frac{1}{2} \left[\begin{array}{ccc}4&-3\\2&-2\end{array}\right] \\ A^{-1}=\left[\begin{array}{ccc}-2& \frac{3}{2}\\-1&1\end{array}\right] [/tex]