Matematika

Pertanyaan

tlng di jwb ya,soalnya buat bsk.Mksh.
No.24 dan 25.
tlng di jwb ya,soalnya buat bsk.Mksh. No.24 dan 25.

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2 Jawaban

  • Garis dan Sudut

    No.24
    <ABD + <CBD = <ABC
    X + 19 + 2X - 1 = 90°
    3X + 18 = 90
    3X = 90 - 18
    3X = 72
    X = 72/3
    X = 24

    Penyiku <CBD = <ABD
    = X + 19
    = 24 + 19
    = 43° (A)

    No.25
    120° + 2a° = 180°
    2a = 180 - 120
    2a = 60
    a = 60/2
    a = 30° (A).

    *semoga membantu. sukses selalu ^_^

  • 24. Sudut ABC = 90°
    Maka. 90° = (x+19)+(2x-1)
    90° = x+2x+19-1
    90° =3x+18
    3x. =90-18
    3x. =72
    x. =72/3
    x. =24

    Sudut CBD = 2x-1
    = 2(24) - 1
    = 47°

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