5log4=p 3log5=q nilai dari 6log240=

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

^5log 4 = p
^5log 2² = p
2 . ^5log 2 = p
^5log 2 = p/2

^6log 240
= (^5log 240)/(^5log 6)
= (^5log (2^3 . 3 . 5))/(^5log (2 . 3))
= (^5log 2^3 + ^5log 3 + ^5log 5)/(^5log 2 + ^5log 3)
= (3 . ^5log 2 + 1/q + 1)/(p/2 + 1/q)
= (3p/2 + 1/q + 1)/(p/2 + 1/q)
= ((3pq + 2 + 2q)/(2q)) / ((pq + 2)/(2q))
= (3pq + 2q + 2)/(pq + 2)