1. tan a + cot a = csc a × sec a 2. tan b × sin b = sec b - cos b tolong jawab ya

[tex]1. \: tan \: a + cot \: a = \cosec \: \: \times sec \: a \\ \frac{sin \: a}{cos \: a} + \frac{cos \: a}{sin \: a} = \cosec \: \: \times sec \: a \\ \frac{sin \: (sin \: a)}{cos \: a \times sin \: a} + \frac{cos \: a(cos \: a}{cos \: a(sin \: a)} = \cosec \: \: \times sec \: a \\ \frac{ {sin}^{2}a + {cos}^{2} a}{cos \: a \times sin \: a} = \cosec \: \: \times sec \: a \\ \frac{1}{cosa \times sina} = \cosec \: \: \times sec \: a \\ cosec \: a \: \times \: sec \: a= \cosec \: \: \times sec \: a \\ terbukti[/tex]
[tex]2. \: tan \: b \: \times sin \: b = sec \: b - \: cos \: b \\ \frac{sin \: b}{cos \: b} \times sin \: b= sec \: b - \: cos \: b \\ \frac{ {sin}^{2}b }{cos \: b} = sec \: b - \: cos \: b \\ \frac{1 - { {cos}^{2}b }}{cos \: b} = sec \: b - \: cos \: b \\ \frac{1}{cos \: b} - \frac{ {cos}^{2}b }{cos \: b} = sec \: b - \: cos \: b \\ sec \: b - cos \: b= sec \: b - \: cos \: b \\ (terbukti)[/tex]