Tolong bantuannya ya!!! *yg di tandain warna merah

= 10x^2/5
= (2/5)10x^2/5-1
= 4x^-3/5
= 4/x^3/5
[tex] \frac{4}{ \sqrt[5]{ {x}^{3} } } [/tex]

F(x) = 10 5^Vx^2
F(x) = 10x^(2/5)
F'(x) = 10(2/5)x^(2/5 - 1)
F'(x) = 4x^(-3/5)

....................4
F'(x) = --------------
..............5^Vx^3



keterangan :
^ = pangkat
5^Vx^3 = akar pangkat 5 dari x pangkat 3
V = akar