koodrinat kutub a(-2akar2,2akar2)

x = -2√2 dan y = 2√2

r = [tex] \sqrt{x^{2}+y^{2} }= \sqrt{ (-2\sqrt{2})^{2}+(2\sqrt{2})^{2}} = \sqrt{8+8} = \sqrt{16} =4[/tex]

cos α = [tex] \frac{x}{r}[/tex]
cos α = [tex] \frac{-2 \sqrt{2} }{4} = -\frac{1}{2} \sqrt{2} [/tex]
α = 135°

Koordinat kutub A(r, α) = A(4, 135°)