Matematika

Pertanyaan

Jika diketahui 2log 3 = x dan 3log 7 = y maka 56log 14 =...

2 Jawaban

  • 56 log 14 = 3 log 14 / 3 log 56
    =3 log 2 x 2 x 7  /  3 log 2 x 2 x 2 x 2 x  7
    = 1/x + 1/x + y  / 1/x + 1/x + 1/x + 1/x + y
    = 2+xy / x  / 4+xy /x
    = 2+xy / 4+xy
  • 2log 3 = log 3 / log 2 = x
    3log 7 = log 7 / log 3 = y
    56log 14 = log 14 / log 56
    = log (7×2) / log (8×7)
    = (log 7 + log 2) / (log 8 + log 7)
    = (log 7 + log 2) / (log 2^3 + log 7)
    = (log 7 + log 2) / (3.log 2 + log 7)
    Ganti bilangan pokok logaritma menjadi 3...
    = (3log 7 + 3log 2) / (3.3log 2 + 3log 7)
    Jadi,
    = ( y + 1/x ) / ( 3/x + y )

    Semoga bermanfaat.....
    -Prisco

Pertanyaan Lainnya