Matematika

Pertanyaan

Jika diketahui 2log 3 = x dan 3log 7 = y maka 56log 14 =...

1 Jawaban

  • 2log 3 = x dan 3log 7 = y,
    56log 14 = log 14 / log 56
    = log (2.7) / log (8.7)
    = (log 2 + log 7) / (log 8 + log 7)
    = (log 2 + log 7) / (log 2^3 + log 7)
    = (log 2 + log 7) / (3. log 2 + log 7)
    beri bilangan pokok logariitma 3. maka
    = (3log 2 + 3log 7) / (3. 3log 2 + 3log 7)
    = (1/x + y ) / (3.1/x + y)
    = (xy + 1)/x / (xy + 3)/x
    = (xy + 1) / (xy + 3)

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