jika tan x = √3 dan sudut lancip, maka sin x =

tan x = √3
tan 60° = √3

x = 60°
sin x = sin 60° = ½√3

tan A = V3
tan A = V3/1
tan.A = y/x, maka y = V3 dan x = 1
r^2 = x^2 + y^2
r^2 = 1^2 + (V3)^2
r^2 = 1 + 3
r^2 = 4
r = +/-V4
r = +/-2
r = 2 ( karena di kuadran 1)
sin A = y/r
sin A = V3/2
sin A = (1/2)V3