Matematika

Pertanyaan

bentuk sederhana dari( x^2.y.z^-3)^2 per (x.y^-2.z^4)2 adalah

1 Jawaban

  • [tex] = \frac{ {( {x}^{2}y {z}^{ - 3} ) }^{2} }{ {(x {y}^{ - 2} {z}^{4} )}^{2} } \\ = \frac{ {x}^{4} {y}^{2} {z}^{ - 6} }{ {x}^{2} {y}^{ - 4} {z}^{8} } \\ = {x}^{4 - 2} {y}^{2 + 4} {z}^{ - 6 - 8} \\ = {x}^{2} {y}^{6} {z}^{ - 14} \\ = \frac{{x}^{2} {y}^{6}}{ {z}^{14} } [/tex]

Pertanyaan Lainnya