Matematika

Pertanyaan

bab SPLADV.....jika (x,y) adalah nilai HP maka carilah
nilai HP/himpunan persamaan
2x(3-4y)
3y(4+x)
dari persamaan berikut!!!
2x+4y = 3x - y + 6
2(x - 2y)= 10
yang teliti yaa..kakak-kakak .,.,.,.,.,.good luck

1 Jawaban

  • 2x+4y = 3x - y + 6
    2x - 3x + 4y + y = 6
    -x + 5y = 6 >>> persamaan 1

    2(x - 2y) = 10
    2x - 4y = 10 >> persamaan 2


    penyetaraan x
    -x + 5y = 6 (kali -2) 2x - 10y = -12
    2x - 4y = 10 (kali 1) 2x - 4y = 10

    eliminasi x
    2x - 10y = -12
    2x - 4y = 10
    ------------------- (-)
    -6y = -22
    y = -22/-6 = 11/3 >>> nilai y

    2x - 4y = 10
    2x = 10 + 4y
    2x = 10 + 4×(11/3)
    2x = 10 + (44/3)
    2x = (30+44)/3
    2x = 74/3
    x = 74/6 = 37/3 >>> nilai x


    nilai HP/himpunan persamaan
    2x(3-4y)
    = 6x - 8xy
    = 6(37/3) - 8 (37/3) (11/3)
    = 222/3 - 3.256/9
    = 666/9 - 3.256/9
    = -2.590/9

    3y(4+x)
    = 12y + 3xy
    = 12 (11/3) + 3 (37/3) (11/3)
    = 132/3 + 1.221/9
    = 396/9 + 1.221/9
    = 1.617/9
    = 539/3


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