Matematika

Pertanyaan

Nilai dari 4log 8 + 8log 256 - 3log 1/27 + 2x 9Log 27

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  • [tex] {}^{4} log8 + {}^{8} log256 - {}^{3} log \frac{1}{27} + 2 \times {}^{9} log27 \\ = {}^{2} log {2}^{ \frac{3}{2} } + {}^{2} log {2}^{ \frac{8}{3} } - {}^{3} log {3}^{ - 3} + {}^{3} log {3}^{3} \\ = \frac{3}{2} + \frac{8}{3} + 3 + 3 = 6 + \frac{25}{6} = \frac{61}{6} = 10 \frac{1}{6} [/tex]

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