Persegi panjang memiliki luas 48cmkubik dengan p:l=3:1. Jika persegi memiliki ukuran sisi =5/6panjang persegi panjang, maka luas persegi adalah..... cmkubik a.

========== Jawaban ==========

Sub. Mapel = Math
Sub. Materi = Bangun Datar
Pertayaan yg diajukan = 1

Penyelesaian :
L = p × l
48 = 3y × y
48 = 3y²
y² = 48/3
y² = 16
y = √16
y = 4 cm

Panjang = 3(y) = 3(4) = 12 cm
Lebar = (y) = (4) = 4 cm

Sisi persegi
= 5/6 × 12 cm
= 10 cm

Luas persegi
= s × s
= 10 cm × 10 cm
= 100 cm²
Opsi D [tex] [/tex]

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Hopefully is the best for you :)

[tex] \frac{p}{l} = \frac{3}{1} \\ p = 3l \\ l = \frac{p}{3} \\ \\ luas \: persegi \: panjang = p \times l \\ p \times l = 48 \\ p \times \frac{p}{3} = 48 \\ {p}^{2} = 144 \\ p = 12cm \\ \\ s = \frac{5}{6} p \\ s = \frac{5}{6} \times 12 = 10cm \\ \\ luas \: persegi = {s}^{2} = {10}^{2} = {100cm}^{2} [/tex]