Matematika

Pertanyaan

64 pangkat 2 per 4 + 32 pangkat negatif 1 per 5

2 Jawaban

  • (64^2 / 4) + (32^-1 / 5) =
    [(4×4×4)^2 / 4] + [(2×2×2×2×2)^-1 / 5]
    = 4^(3×2) / 4^1 + 2^(5×(-1)) / 5
    = 4^6 / 4^1 + 2^-5 / 5
    = 4^(6-1) + (1/2)^5 / 5 = 4^5 + 1/32 × 1/5
    = 1024 + 1/160
  • 64^2/4+32^-1/5
    = 64^1/2+32^-1/5
    = (8^2)^1/2+(2^5)^-1/5
    = 8^1+2^-1
    = 8+(-2)
    = 6

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