tentukan nilai dari 4√18-√32+3√8

4√18-√32+3√8
(4x3√2) - 4√2 + (3x2√2)

12√2 - 4√2 + 6√2 = 14√2

[tex] = 4 \sqrt{2 \times 9} - \sqrt{2 \times 16} + 3 \sqrt{2 \times 4} \\ = 4\times 3 \sqrt{2} - 4 \sqrt{2} + 3 \times 2 \sqrt{2} \\ = 12 \sqrt{2} - 4 \sqrt{2} + 6 \sqrt{2} \\ = (12 + 6 - 4) \sqrt{2} \\ = 14 \sqrt{2} [/tex]