Bentuk sederhana (a. b) 3.(a.3.b2)-1
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Pertanyaan
Bentuk sederhana (a. b) 3.(a.3.b2)-1
1 Jawaban
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1. Jawaban therealcandra
[tex] = {(ab)}^{3} .( {a}^{3} {b}^{2})^{ - 1} \\ = \frac{ {(ab)}^{3} }{ {a}^{3} {b}^{2}} \\ = \frac{ {a}^{3} {b}^{3} }{ {a}^{3} {b}^{2} } \\ = {a}^{3 - 3} {b}^{3 - 2} \\ = {a}^{0} b \\ = b[/tex]