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Pertanyaan

Ph larutan garam (NH4)3PO4 0.3 M (Kb= 10^-5)

1 Jawaban

  • [H+] = √Kw/Kb . [B+]
    = √10^-14/10^-5 . 9.10^-1
    = √9.10^-10
    = 3.10^-5
    pH = - log [H+]
    = - log 3.10^-5
    = 5 - log 3

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