Ph larutan garam (NH4)3PO4 0.3 M (Kb= 10^-5)
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Pertanyaan
Ph larutan garam (NH4)3PO4 0.3 M (Kb= 10^-5)
1 Jawaban
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1. Jawaban KMB8799
[H+] = âKw/Kb . [B+]
= â10^-14/10^-5 . 9.10^-1
= â9.10^-10
= 3.10^-5
pH = - log [H+]
= - log 3.10^-5
= 5 - log 3