1. Jika f(x)= 3xpangkat2+2x-1 maka f(1)= 3. Misal f(x)=xpangkat2-7x+15. Jika f(a)=5 maka nilai a yang memenuhi adalah= 4. Misal f(2)= 4 dan f(x+3)= f(x)+5 maka

1.
f(x) = 3x² + 2x - 1
f(1) = 3(1)² + 2(1) - 1 = 4

3.
f(x) = x² - 7x + 15
f(a) = a² - 7a + 15 = 5
= a² - 7a + 10 = 0
= (a - 5) (a - 2) = 0
a = 5 atau a = 2

4.
f(2) = 4
f(x + 3) = f(x) + 5
f(2 + 3) = f(2) + 5
f(5) = 4 + 5 = 9

f(x + 3) = f(x) + 5
f(5 + 3) = f(5) + 5
f(8) = 9 + 5 = 14

5.
f(x - 3) = 4x + 1
→ f(5 - 3) = 4(5) + 1
→ f(2) = 21

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