Matematika

Pertanyaan

Tolong cari kan ya.........
Tolong cari kan ya.........

1 Jawaban

  • a) <ACB = 1/2 x 120° = 60°
    b) Luas juring AOB= 120°/360°x22/7x14x14
    = 205,3 cm²
    c) panjang busur AB= 120°/360°x2x22/7xπxr
    = 29,3 cm
    d) Keliling O = 2 πr = 2 x 22/7 x 14 = 88cm
    e) Luaa O = π r² = 22/7 x 14 x14 = 616 cm²