jika f(x)=2x+3 per x-8 dimana x= 1 per 8 tentukanlah f^-1 (x+2)=

y = (2x + 3)/(x - 8)
y(x - 8) = 2x + 3
xy - 8y = 2x + 3
xy - 2x = 8y + 3
x(y - 2) = 8y + 2
x = (8y + 2)/(y - 2)
f^-1(x) = (8x + 2)/(x - 2)
f^-1(x + 2) = (8(x + 2) + 2)/(x + 2 - 2)
= (8x + 18)/x