Persamaan garis singgung x2+y2-6x+10y +29=0 yg sejajar garis 2x-y-5=0
Matematika
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Pertanyaan
Persamaan garis singgung x2+y2-6x+10y +29=0 yg sejajar garis 2x-y-5=0
1 Jawaban
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1. Jawaban nisa2421
[tex]a = - \frac{1}{2} \times ( - 6) = 3 \\ b = - \frac{1}{2} \times 10 = - 5 \\ c = 29 \\ r = \sqrt{ {a}^{2} + {b}^{2} - c } \\ r = \sqrt{ {3}^{2} + { (- 5)}^{2} - 29 } \\ r = \sqrt{9 + 25 - 29} \\ r = \sqrt{5} \\ 2x - y - 5 = 0 \\ 2x - 5 = y \\m = 2 \\ pgs \\( y - b) = m(x - a) \frac{ + }{} r \sqrt{ {m}^{2} + 1} \\ (y + 5) = 2(x - 3) \frac{ + }{} \sqrt{5} \sqrt{{2}^{2} + 1 } \\ y= 2x - 6 - 5 \frac{ + }{} \sqrt{5} \sqrt{5} \\ y = 2x - 11 \frac{ + }{} 5 \\ y = 2x - 6 \: atau \: \\ y = 2x - 16[/tex]