Nilai dari sin195° + sin105° dibagi cos120° - cos300°

[tex] \frac{ \sin(195) + \sin(105) }{ \cos(120) - \cos(300)} \\ = \frac{ 2 \sin( \frac{195 + 105}{2} ) \cos( \frac{195 - 105}{2})}{ - 2 \sin( \frac{120 + 300}{2}) \sin( \frac{120 - 300}{2})} \\ = \frac{2 \sin(150) \cos(45)}{ - 2 \sin(210) \sin( - 90) } \\ = \frac{2 \times \frac{1}{2} \times \frac{1}{2} \sqrt{2} }{ - 2 \times ( - \frac{1}{2}) \times ( - 1) } \\ = - \frac{1}{2} \sqrt{2} [/tex]