Matematika

Pertanyaan

turunan pertama dari (f)x=sin4(3xkuadrat-4)adalah

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  • [tex]f(x) = { \sin }^{4} ( {3x}^{2} - 4) \\ f'(x) = 4 { \sin }^{3} ( {3x}^{2} - 4) \cos ( {3x}^{2} - 4) 6x \\ f'(x) = 24x { \ \sin }^{3} ( {3x}^{2} - 4) \cos( {3x}^{2} - 4) \\ f'(x) = 12x.2 \: { \sin }^{2} ( {3x}^{2} - 4) \sin( {3x}^{2} - 4) \cos( {3x}^{2} - 4) \\ f'(x) = 12x \: { \sin }^{2} {(3x}^{2} - 4) \sin2( {3x}^{2}- 4) \\ f'(x) = 12x \: { \sin }^{2} ( {3x}^{2} - 4)( {6x}^{2} - 8)[/tex]

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