larutan 100 mL asam sulfat (H2SO4) = 0,05 M mempunyai pH sebesar? bantu ya

Mapel: Kimia
Kelas: XI
Materi Asam Basa

Jawab

H2SO4 → 2H+ + SO4²-
V= 2

[H+] = 2×0.05
[H+] = 0.1
[H+] = 1×10-¹

pH= -log[H+]
pH= -log1×10-¹
pH= 1-log1
pH= 1-0
pH= 1