tentukan nilai limit berikut

[tex] = \frac{ {x}^{2} - 8x + 15}{x - 3} \\ = \frac{(x - 3)(x - 5)}{x - 3} \\ = x - 5 \\ = (3) - 5 = - 2 \: (B)\\ [/tex]
[tex] = \frac{ {x}^{2} + x - 6}{x - 2} \\ = \frac{(x - 2)( x + 3)}{x - 2} \\ = x + 3 \\ = (2) + 3 = 5 \: (C) [/tex]