Tentukan turunan pertama fungsi f (x) = 2 sin^2 2x

[tex]\frac{dy}{dv} \cdot \frac{dv}{du} \cdot \frac{du}{dx}=\frac{dy}{dx}[/tex]
[tex]u = 2x[/tex]
[tex]v = sin(u)[/tex]
[tex]\frac{d}{dv}2v^2\cdot\frac{d}{du}sin(u) \cdot \frac{d}{dx}2x = \frac{dy}{dx}[/tex]
[tex]\frac{d}{dv}2v^2\cdot\frac{d}{du}sin(u) \cdot \frac{d}{dx}2x = 4v\cdot cos(u)\cdot 2[/tex]
[tex]4sin(2x)\cdot cos(2x)\cdot 2[/tex]
[tex]2sin(2x)cos(2x)\cdot 4 = 4sin(4x)[/tex]