Tentukan fungsi invers dari fungsi f(x)=x(x+2) beserta caranya

f(x) = x (x+2)
[tex]y = {x}^{2} + 2x \\ y = {x}^{2} + 2x + 1 - 1 \\ y = {(x + 1)}^{2} - 1 \\ {(x + 1)}^{2} = y + 1 \\ x + 1 = \sqrt{y + 1 } \\ x = \sqrt{y + 1} - 1 \\ {f}^{ - 1} (x) = \sqrt{x + 1} - 1[/tex]