Matematika

Pertanyaan

tolong dijawab no. 22,24,27! please pake cara!
tolong dijawab no. 22,24,27! please pake cara!

1 Jawaban

  • 22)
    Misal lebar = x cm
    panjang = (x + 4) cm

    Keliling < 48
    2 (p + l) < 48
    2 (x + 4 + x) < 48
    2 (2x + 4) < 48
    4x + 8 < 48
    4x < 48 - 8
    4x < 40
    [tex]x < \frac{40}{4} [/tex]
    x < 10 cm

    Jawaban : C. x < 10

    24)
    [tex]4x + 5 \leqslant 6x - 3 \\ 4x - 6x \leqslant - 3 - 5 \\ - 2x \leqslant - 8 \\ x \geqslant 4[/tex]
    Jawaban : B


    27)
    [tex] \frac{1}{5} x - 7 < 1 \\ x - 35 < 5 \\ x < 5 + 35 \\ x < 40[/tex]

    Jawaban : D