[tex]sebuah \: persamaan \\ 2f(x) = \frac{ {x}^{2} + 1}{ {x}^{2} } + \frac{1}{x} [/tex] maka f(x) = ....
Matematika
chrisayuni
Pertanyaan
[tex]sebuah \: persamaan \\ 2f(x) = \frac{ {x}^{2} + 1}{ {x}^{2} } + \frac{1}{x} [/tex]
maka f(x) = ....
maka f(x) = ....
1 Jawaban
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1. Jawaban JessicaHuang20
[tex]2f(x) = \frac{ {x}^{2} + 1 }{ {x}^{2} } + \frac{1}{x} \\ f(x) = \frac{ \frac{ {x}^{2} + 1 }{ {x}^{2} } }{2} + \frac{ \frac{1}{x} }{2} \\ f(x) = (\frac{ {x}^{2} + 1}{ {x}^{2} } \times \frac{1}{2}) + ( \frac{1}{x} \times \frac{1}{2} ) \\ f(x) = \frac{ {x}^{2} + 1}{2 {x}^{2} } + \frac{1}{2x} \\ f(x) = \frac{ {x}^{2} + 1 + x }{2 {x}^{2} } = \frac{ {x}^{2} + x + 1 }{2 {x}^{2} } [/tex]
semoga membantu^^