Jika 6log 3 = x, dan 6log 2 = y, maka 6log2/27 √2 adalah...

[tex] = 6 log \frac{2}{27 \sqrt{2} } \\ = 6log2 - 6log27 \sqrt{2} \\ = 6log2 - (6log27 + 6log \sqrt{2} ) \\ = 6log2 - (6log {3}^{3} + 6log {2}^{ \frac{1}{2} } ) \\ = 6log2 - (3.6log3 + \frac{1}{2} .6log2) \\ = y - (3x + \frac{1}{2} y) \\ = y - \frac{1}{2} y - 3x \\ = \frac{1}{2} y - 3x[/tex]